mes

Published on May 28, 2020
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In this video I go over the derivative of inverse hyperbolic tangent or tanh-1(x) and show that it is equal to 1/(1-x2).

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Related Videos:

Derivative of Inverse Hyperbolic Trigonometry: sinh-1(x): http://youtu.be/s0sk4OR5hV4
Derivative of Inverse Hyperbolic Trigonometry: cosh-1(x): http://youtu.be/ETLaLCpGwLI
Derivatives of Hyperbolic Trigonometry: coth(x): http://youtu.be/4EkTEYFMOqI
Implicit Differentiation - A Brief Introduction: http://youtu.be/12OY1b3DYHQ
Hyperbolic Trigonometry Identity Proof: cosh2(x) - sinh2(x) = 1: http://youtu.be/-UXUqIWRNEA
Absolute Values - Properties and Rules: http://youtu.be/tl9iten87MU
Derivative of Inverse Hyperbolic Trigonometry: sinh-1(x): http://youtu.be/s0sk4OR5hV4
Hyperbolic Functions - tanh(x), sinh(x), cosh(x) - Introduction: http://youtu.be/EmJKuQBEdlc
Inverse Hyperbolic Trigonometry as Logarithms: cosh-1(x): http://youtu.be/lsUcHzQAlHQ
Inverse Hyperbolic Trigonometry as Logarithms: tanh-1(x): http://youtu.be/vfOWS8Y_rQw
Inverse Hyperbolic Trigonometry as Logarithms: csch-1(x): http://youtu.be/278-6zKYDdE
Inverse Hyperbolic Trigonometry as Logarithms: sech-1(x): http://youtu.be/cF0Pbdkae30
Inverse Hyperbolic Trigonometry as Logarithms: coth-1(x): http://youtu.be/x0qIdT0BrHI .


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